Joseph Fry - tea merchant from England. Article “Joseph Fry (tea merchant)” in English Wikipedia has 29.1 points for quality (as of July 1, 2025). The article contains 13 references and 7 sections.
In June 2025 the article “Joseph Fry (tea merchant)” was edited by 1 authors in English Wikipedia and written by 1 authors in all languages.
Since the creation of article “Joseph Fry (tea merchant)”, its content was written by 31 registered users of English Wikipedia and edited by 31 registered Wikipedia users in all languages.
The article is cited 7 times in English Wikipedia and cited 7 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | English: #659788 05.2013 |
Global: #1132686 05.2013 |
| Best Rank | English: #121681 08.2013 |
Global: #342925 08.2008 |
On 5 March 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: Iran, Ali Khamenei, 2026 Iran war, Jeffrey Epstein, Kurds, Strait of Hormuz, Yakovlev Yak-130, Donald Trump, Azerbaijan, Kristi Noem.
In English Wikipedia the most popular articles on that day were: Markwayne Mullin, Kristi Noem, 2026 Iran war, Ali Khamenei, Lou Holtz, Men's T20 World Cup, Iran, IRIS Dena, Corey Lewandowski, Deaths in 2026.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(15.75+10.57+0+50+68.97)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
